The inequality given in the image is:

$-8 + 3x < -5$

Solution:

1. Isolate the term with $x$: Add $8$ to both sides to simplify: $-8 + 8 + 3x < -5 + 8$ $3x < 3$

2. Solve for $x$: Divide both sides by $3$: $x < 1$

Final Answer:

$x < 1$

Let me know if you want further details or clarification! Below are some related questions to expand your understanding:

Related Questions:

1. How would the solution change if the inequality were $-8 + 3x > -5$?
2. What is the graphical representation of $x < 1$ on a number line?
3. How does the solution change when dividing by a negative number in inequalities?
4. What happens if the inequality includes "or equal to" (e.g., $-8 + 3x \leq -5$)?
5. How do we check if a specific value satisfies the inequality?

Tip:

When solving inequalities, always remember to reverse the inequality sign if multiplying or dividing by a negative number!