We are tasked with finding which ordered pair satisfies the inequality $7x - 3y > 10$. Let's check each pair by substituting $x$ and $y$ values into the inequality:

1. For $(2, 1)$:

$7(2) - 3(1) = 14 - 3 = 11$ Since $11 > 10$, this pair satisfies the inequality.

2. For $(1, 0)$:

$7(1) - 3(0) = 7 - 0 = 7$ Since $7 \not> 10$, this pair does not satisfy the inequality.

3. For $(1, -1)$:

$7(1) - 3(-1) = 7 + 3 = 10$ Since $10 \not> 10$, this pair does not satisfy the inequality.

4. For $(3, 4)$:

$7(3) - 3(4) = 21 - 12 = 9$ Since $9 \not> 10$, this pair does not satisfy the inequality.

Thus, the correct answer is the pair (2, 1).

Would you like more details on any step or have further questions?

Here are five related questions:

1. How do we solve linear inequalities with two variables?
2. What is the difference between solving equations and inequalities?
3. How do you graph the solution to a linear inequality?
4. Can a solution to an inequality be on the boundary line?
5. How do we solve systems of inequalities?

Tip: When testing points in inequalities, always substitute both variables and simplify carefully to ensure the correct comparison!