Math Problem Statement

Solve the inequality: -(3x + 3) - 2x > -4(x - 2) - 2

Solution

The inequality provided in the image is:

(3x+3)2x>4(x2)2-(3x + 3) - 2x > -4(x - 2) - 2

Step-by-step solution:

  1. Expand both sides:

    • On the left:
      (3x+3)=3x3-(3x + 3) = -3x - 3 So the left-hand side becomes:
      3x32x=5x3-3x - 3 - 2x = -5x - 3
    • On the right:
      4(x2)=4x+8-4(x - 2) = -4x + 8 So the right-hand side becomes:
      4x+82=4x+6-4x + 8 - 2 = -4x + 6
  2. Rewrite the inequality: 5x3>4x+6-5x - 3 > -4x + 6

  3. Add 4x4x to both sides to move xx terms to one side: 5x+4x3>6-5x + 4x - 3 > 6 Simplifying: x3>6-x - 3 > 6

  4. Add 3 to both sides: x>9-x > 9

  5. Multiply both sides by -1 (remember to flip the inequality sign): x<9x < -9

Final solution:

The inequality is x<9x < -9. Therefore, the correct answer is:

x<9\boxed{x < -9}

Would you like further details on any part of the process or additional related questions?


Related Questions:

  1. How do you solve linear inequalities with fractions?
  2. What happens when you multiply or divide an inequality by a negative number?
  3. How do you check if your solution to an inequality is correct?
  4. What are the different ways to express inequality solutions (interval notation, graphing, etc.)?
  5. How would the solution change if the inequality symbol were \geq instead of >>?

Tip: Always remember to flip the inequality sign when multiplying or dividing by a negative number!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Inequalities

Formulas

Distributive Property
Simplifying Expressions

Theorems

Properties of Inequalities
Rule of Multiplying/Dividing Inequalities by Negative Numbers

Suitable Grade Level

Grades 8-10