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The inequality provided is:

\[
\frac{2x + 1}{3} \geq 5
\]

To solve this inequality, follow these steps:

1. **Multiply both sides by 3** (to eliminate the fraction):

   \[
   2x + 1 \geq 15
   \]

2. **Subtract 1 from both sides**:

   \[
   2x \geq 14
   \]

3. **Divide both sides by 2**:

   \[
   x \geq 7
   \]

The solution to the inequality is \( x \geq 7 \).

Would you like more details or have any questions?

### Related Questions:
1. How would the solution change if the inequality were \( \frac{2x + 1}{3} \leq 5 \)?
2. What are some different methods to solve inequalities?
3. How does multiplying or dividing by a negative number affect an inequality?
4. Can inequalities be solved graphically? If so, how?
5. How would you solve a compound inequality, such as \( 2 \leq \frac{2x + 1}{3} < 5 \)?

### Tip:
Always remember to reverse the inequality sign when multiplying or dividing both sides by a negative number.

Learn how to solve the linear inequality (2x + 1) / 3 ≥ 5 with a step-by-step breakdown. This solution covers key algebra concepts and is suitable for students in Grades 8-10.

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