The inequality provided is:

$\frac{2x + 1}{3} \geq 5$

To solve this inequality, follow these steps:

1. Multiply both sides by 3 (to eliminate the fraction):

   $2x + 1 \geq 15$

2. Subtract 1 from both sides:

   $2x \geq 14$

3. Divide both sides by 2:

   $x \geq 7$

The solution to the inequality is $x \geq 7$.

Would you like more details or have any questions?

Related Questions:

1. How would the solution change if the inequality were $\frac{2x + 1}{3} \leq 5$?
2. What are some different methods to solve inequalities?
3. How does multiplying or dividing by a negative number affect an inequality?
4. Can inequalities be solved graphically? If so, how?
5. How would you solve a compound inequality, such as $2 \leq \frac{2x + 1}{3} < 5$?

Tip:

Always remember to reverse the inequality sign when multiplying or dividing both sides by a negative number.