The given inequality is:

$-2x + 3y \geq 10$

To solve this inequality or express it in a more useful form, you can isolate $y$. Let's go through the steps:

1. Add $2x$ to both sides to move the $-2x$ term: $3y \geq 2x + 10$

2. Divide both sides by 3 to solve for $y$: $y \geq \frac{2x + 10}{3}$

This is the solution in terms of $y$. The inequality tells you that for any value of $x$, $y$ must be greater than or equal to $\frac{2x + 10}{3}$.

If you wish to graph this inequality, the boundary line is the equation $y = \frac{2x + 10}{3}$, and you would shade the region above this line since $y \geq \frac{2x + 10}{3}$.

Would you like to explore the graph of this inequality or need further explanation on any step?

Here are some related questions for further learning:

1. How do you graph a linear inequality like this one?
2. What happens if you reverse the inequality to $-2x + 3y \leq 10$?
3. What does the slope of the line $y = \frac{2x + 10}{3}$ represent?
4. How would you solve a system of linear inequalities involving this inequality?
5. What are the differences between solving linear equalities vs. inequalities?

Tip: When graphing linear inequalities, always remember that the line is either solid (for $\geq$ or $\leq$) or dashed (for $>$ or $<$), and the shading indicates the region that satisfies the inequality.