We are tasked with finding the inequality that can be solved to determine how many weeks Ricky must save in order to afford a video camera costing $850.

Here's a breakdown:

• Ricky has $300 already.
• He saves an additional $40 per week.
• The total amount he needs is $850.

The inequality should represent the sum of his initial amount ($300) and the additional savings per week ($40 times the number of weeks, t), which needs to be at least $850.

This leads us to the equation: $300 + 40t \geq 850$

This represents the total amount Ricky will have after saving for t weeks, which should be greater than or equal to $850.

The correct inequality is: $\boxed{C. \ 300 + 40t \geq 850}$

Would you like me to show the step-by-step solution for solving this inequality, or do you have any other questions?

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Here are 5 related questions:

1. How would you solve the inequality $300 + 40t \geq 850$ to find the value of $t$?
2. What would the inequality look like if Ricky saved $50 per week instead?
3. If the camera cost $950, how would the inequality change?
4. How many weeks would Ricky need if he had only $200 saved initially?
5. What if Ricky increased his weekly savings by $10 after 5 weeks?

Tip: When dealing with inequalities, always remember to reverse the inequality sign when multiplying or dividing by a negative number.