Math Problem Statement

Neil starts with $20 in his bank account. Every week, he deposits $60. For how many weeks might he have been depositing money if his account balance is now at least $380? Write an inequality to represent the situation. Use x to represent the number of weeks. Nice! You just wrote an inequality to represent the situation. Now solve the associated equation, 20 + 60x = 380, to find the boundary for the inequality. Show your work or solve on paper. 20 + 60x ≥ 380 20+60x

380

x

You got it! You found that x = 6 is the solution to the associated equation. Is x = 6 also included in the solutions to the inequality? 20 + 60x ≥ 380

Yes

No Excellent! You found that x = 6 makes the inequality true. Now test a value below the boundary, x = 5, and a value above the boundary, x = 7. Do they make the inequality true or false? x= 5 x=6 (boundary) x= 7 20 + 60x ≥ 380 True

Solution

Let's break this down step by step and ensure everything is clear.

1. Writing the inequality:

Neil starts with $20 and deposits $60 every week. If his account balance is at least $380, we can write the inequality as: 20+60x38020 + 60x \geq 380 where xx represents the number of weeks.

2. Solving the equation to find the boundary:

Now, we solve the equation 20+60x=38020 + 60x = 380 to find the boundary value: 20+60x=38020 + 60x = 380 Subtract 20 from both sides: 60x=36060x = 360 Divide both sides by 60: x=6x = 6

So, x=6x = 6 is the boundary.

3. Is x=6x = 6 included in the solutions to the inequality?

Since the inequality is 20+60x38020 + 60x \geq 380, this means that x=6x = 6 is included because the inequality uses "greater than or equal to" (≥), which allows equality.

Thus, Yes, x=6x = 6 is included in the solutions.

4. Testing x=5x = 5 and x=7x = 7:

Now, let's check if x=5x = 5 and x=7x = 7 make the inequality true or false.

When x=5x = 5:

Substitute x=5x = 5 into the inequality: 20+60(5)=20+300=32020 + 60(5) = 20 + 300 = 320 Since 320320 is less than 380, the inequality is false for x=5x = 5.

When x=6x = 6 (boundary):

Substitute x=6x = 6 into the inequality: 20+60(6)=20+360=38020 + 60(6) = 20 + 360 = 380 Since 380380380 \geq 380 is true, the inequality is true for x=6x = 6.

When x=7x = 7:

Substitute x=7x = 7 into the inequality: 20+60(7)=20+420=44020 + 60(7) = 20 + 420 = 440 Since 440380440 \geq 380 is true, the inequality is true for x=7x = 7.

Summary:

  • x=6x = 6 is included because it satisfies the inequality.
  • For x=5x = 5, the inequality is false.
  • For x=7x = 7, the inequality is true.

Would you like to go over more examples or clarify anything?

Additional Questions:

  1. What would the equation be if Neil started with a different amount, say $30?
  2. If Neil deposited $50 per week instead of $60, what would the equation look like?
  3. How would the inequality change if Neil's account balance needed to be at least $400 instead of $380?
  4. If the inequality were 20+60x>38020 + 60x > 380, would x=6x = 6 still be a solution?
  5. How would you graph the inequality 20+60x38020 + 60x \geq 380 on a number line?

Tip: Always check if the inequality includes equality (≥ or ≤), as this can affect whether boundary values are included in the solution.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Inequalities

Formulas

20 + 60x ≥ 380
20 + 60x = 380

Theorems

Solving linear inequalities
Solving linear equations

Suitable Grade Level

Grades 7-9