Let's solve some of these inequalities step by step. I'll start with problem 2 from the image. If you have a particular one you'd like to focus on, let me know!

Problem 2:

$\frac{x + 4}{3} \leq \frac{1}{2}$

Step 1: Eliminate the fraction by multiplying both sides by 3:

$x + 4 \leq \frac{1}{2} \times 3 = \frac{3}{2}$

Step 2: Subtract 4 from both sides:

$x \leq \frac{3}{2} - 4$ $x \leq \frac{3}{2} - \frac{8}{2} = -\frac{5}{2}$

Thus, the solution in interval notation is: $(-\infty, -\frac{5}{2}]$

Let me know if you'd like to go through another problem or need details for this one. Here are 5 possible related questions:

1. Would you like to solve problem 4 next?
2. How would the solution change if the inequality were strict (i.e., $<$ instead of $\leq$)?
3. Can you explain how to convert the inequality into interval notation?
4. What is the effect of multiplying or dividing by a negative number in inequalities?
5. Would you like to go through how to check the solution graphically?

Tip: When solving inequalities, remember that multiplying or dividing by a negative number reverses the inequality sign!