You have a system of linear equations:

1. $y = -x + 5$
2. $y = 2x - 1$

To find the solution for this system, set the expressions for $y$ equal to each other:

$-x + 5 = 2x - 1$

Solve for $x$:

1. Add $x$ to both sides:

   $5 = 3x - 1$

2. Add 1 to both sides:

   $6 = 3x$

3. Divide both sides by 3:

   $x = 2$

Now, substitute $x = 2$ back into either of the original equations to find $y$. Using the second equation:

$y = 2(2) - 1 = 4 - 1 = 3$

Thus, the solution to the system of equations is $x = 2$ and $y = 3$. The point of intersection is $(2, 3)$.