Math Problem Statement

Solve for a: \(\frac{3a}{2} + 15 + \frac{2a}{3} = 25\). Select the correct option from the following: a. \(\frac{6}{13}\), b. \(\frac{60}{13}\), c. \(\frac{13}{60}\), d. \(\frac{10}{13}\).

Solution

Let's solve the equation from the image:

3a2+15+2a3=25\frac{3a}{2} + 15 + \frac{2a}{3} = 25

Step 1: Combine like terms

First, isolate the terms involving aa on one side of the equation. Start by subtracting 15 from both sides:

3a2+2a3=2515\frac{3a}{2} + \frac{2a}{3} = 25 - 15

This simplifies to:

3a2+2a3=10\frac{3a}{2} + \frac{2a}{3} = 10

Step 2: Find a common denominator

To add the fractions 3a2\frac{3a}{2} and 2a3\frac{2a}{3}, we need to find a common denominator. The least common denominator (LCD) of 2 and 3 is 6.

Rewrite both fractions with a denominator of 6:

3a2=9a6,2a3=4a6\frac{3a}{2} = \frac{9a}{6}, \quad \frac{2a}{3} = \frac{4a}{6}

Now, combine the fractions:

9a6+4a6=13a6\frac{9a}{6} + \frac{4a}{6} = \frac{13a}{6}

So the equation becomes:

13a6=10\frac{13a}{6} = 10

Step 3: Solve for aa

To get rid of the fraction, multiply both sides of the equation by 6:

13a=10×613a = 10 \times 6

13a=6013a = 60

Now, divide both sides by 13:

a=6013a = \frac{60}{13}

Final Answer:

The value of aa is 6013\frac{60}{13}, which corresponds to option b.

Would you like more details or have any questions?

Related Questions:

  1. How would you solve the equation if the fractions had different variables?
  2. What is the least common denominator and how is it useful in solving equations with fractions?
  3. How can you verify the solution by substituting the value of aa back into the original equation?
  4. How would the process differ if there was a negative term in the equation?
  5. How can we solve equations with three or more fractions?

Tip:

Always check your work by substituting the solution back into the original equation to verify its accuracy.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Fractions

Formulas

Combining like terms
Finding the least common denominator (LCD) for fractions

Theorems

Linear Equation Solving

Suitable Grade Level

Grades 7-9