To move the $-2h$ from the right side of the equation and have all the $h$-terms on the left side, the correct move would be to add $2h$ to both sides of the equation.

Here’s why:

Starting with the equation: $6h + 4 = -2h + 6$

If you want to get rid of the $-2h$ on the right-hand side, you add $2h$ to both sides to move the $h$-terms to the left:

$6h + 4 + 2h = -2h + 6 + 2h$

This simplifies to: $8h + 4 = 6$

Now, all the $h$-terms are on the left side. This is the appropriate step.

The correct answer is: Add 2h to each side.

Would you like further explanation on this? Or do you have other questions related to equations?

Here are 5 related questions:

1. How do you solve for $h$ in the equation $8h + 4 = 6$?
2. What happens when you divide both sides of an equation by a variable?
3. How do you combine like terms in an equation?
4. What is the difference between adding and subtracting terms when solving an equation?
5. How can you check if your solution to an equation is correct?

Tip: Always ensure to keep the variable terms on the same side by performing the same operation on both sides of the equation.