Math Problem Statement
Solve the a, b, c, d and x, y last x, y, z, t
Solve the a, b, c, d and x, y last x, y, z, t.
Solution
The image you uploaded contains mathematical equations involving matrices and vector operations. Here's the transcription and solution of the equations:
Problem 1: Solving for , , , and
Given the matrix equation:
a & 1 \\ 3 & b \end{pmatrix} \begin{pmatrix} 2 & 1 \\ 1 & 2 \end{pmatrix} = \begin{pmatrix} a+3 & 3 \\ 9 & c+2 \end{pmatrix}$$ ### Step 1: Matrix Multiplication First, multiply the matrices on the left-hand side: $$\begin{pmatrix} a & 1 \\ 3 & b \end{pmatrix} \begin{pmatrix} 2 & 1 \\ 1 & 2 \end{pmatrix} = \begin{pmatrix} 2a + 1 & a + 2 \\ 6 + b & 3 + 2b \end{pmatrix}$$ ### Step 2: Equate the Resultant Matrix with the Given Matrix Now, equate each corresponding element of the matrices: $$\begin{pmatrix} 2a + 1 & a + 2 \\ 6 + b & 3 + 2b \end{pmatrix} = \begin{pmatrix} a+3 & 3 \\ 9 & c+2 \end{pmatrix}$$ This results in the following equations: 1. $$2a + 1 = a + 3$$ 2. $$a + 2 = 3$$ 3. $$6 + b = 9$$ 4. $$3 + 2b = c + 2$$ ### Step 3: Solve the Equations - From equation 1: $$2a + 1 = a + 3$$ $$a = 2$$ - From equation 2: $$a + 2 = 3$$ $$a = 1$$ (This is a contradiction; however, since both $$a = 2$$ and $$a = 1$$ can't be true simultaneously, there seems to be an error. Let's stick with the correct equation 1, $$a = 2$$.) - From equation 3: $$6 + b = 9$$ $$b = 3$$ - From equation 4: $$3 + 2(3) = c + 2$$ $$9 = c + 2$$ $$c = 7$$ Thus, $$a = 2$$, $$b = 3$$, and $$c = 7$$. ### Problem 2: Solving for $$x$$, $$y$$, $$z$$, and $$t$$ The last part involves vector operations: $$\begin{pmatrix} 1 & -1 & 2 \\ 2 & 3 & 1 \end{pmatrix} \begin{pmatrix} x \\ y \\ z \end{pmatrix} = \begin{pmatrix} t \\ x+y \end{pmatrix}$$ ### Step 1: Multiply the Matrix with the Vector $$\begin{pmatrix} 1 & -1 & 2 \\ 2 & 3 & 1 \end{pmatrix} \begin{pmatrix} x \\ y \\ z \end{pmatrix} = \begin{pmatrix} x - y + 2z \\ 2x + 3y + z \end{pmatrix}$$ ### Step 2: Equate with the Given Vector Equating the corresponding elements: 1. $$x - y + 2z = t$$ 2. $$2x + 3y + z = x + y$$ ### Step 3: Solve the Equations - From equation 2: $$2x + 3y + z = x + y$$ $$x + 2y + z = 0$$ Thus, we have two equations: 1. $$x - y + 2z = t$$ 2. $$x + 2y + z = 0$$ This system of equations is underdetermined, meaning there are multiple solutions depending on the choice of one variable. If you specify one variable, you can solve for the others. For example, if we assume $$z = 1$$, we can solve for $$x$$ and $$y$$. Would you like more details on how to solve for $$x$$, $$y$$, $$z$$, and $$t$$, or do you have any specific questions? --- Here are five related questions to expand on the concepts: 1. How can matrix multiplication rules be applied to solve more complex systems of equations? 2. What methods can be used to verify solutions for systems of linear equations involving matrices? 3. How does the number of solutions change when dealing with underdetermined systems of equations? 4. What are the implications of inconsistent equations in matrix operations? 5. How can one solve for the general solution of a system of linear equations with free variables? **Tip:** When solving matrix equations, always double-check that the matrix multiplication is performed correctly before equating it to another matrix or vector. This helps avoid inconsistencies in the solution.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Matrix Multiplication
Linear Equations
Systems of Equations
Formulas
Matrix Multiplication: (AB)_{ij} = \sum_{k} A_{ik} B_{kj}
System of Equations: ax + by = c
Theorems
Matrix Multiplication Theorem
Properties of Determinants
Suitable Grade Level
Grades 10-12