Let's solve each equation step by step using algebraic methods:

1. Equation: $6x = 17$ To solve for $x$, divide both sides by 6: $x = \frac{17}{6} \approx 2.83$ So, $x \approx 2.83$.

2. Equation: $19.2(2.1)x = 50.3$ First, simplify the constant multiplication on the left side: $19.2 \times 2.1 = 40.32$ Now, the equation becomes: $40.32x = 50.3$ To solve for $x$, divide both sides by 40.32: $x = \frac{50.3}{40.32} \approx 1.25$ So, $x \approx 1.25$.

3. Equation: $7 = 102(0.72)x$ Simplify the multiplication on the right side: $102 \times 0.72 = 73.44$ Now, the equation becomes: $7 = 73.44x$ To solve for $x$, divide both sides by 73.44: $x = \frac{7}{73.44} \approx 0.095$ So, $x \approx 0.095$.

Final Answers:

1. $x \approx 2.83$
2. $x \approx 1.25$
3. $x \approx 0.095$

Would you like more details or have any other questions on these problems?

Here are some related questions to explore:

1. What happens if we solve these equations using different methods (like substitution or elimination)?
2. How can we check the solutions to ensure they are correct?
3. How do you solve equations with fractional or decimal coefficients in general?
4. What is the importance of the distributive property in simplifying equations?
5. What would change if the constants in the equations were negative?

Tip: Always check your work by substituting your value of $x$ back into the original equation to verify your solution is correct!