Math Problem Statement

Joy is younger than Yaritza.their ages are consecutive odd integers.Find joys age if the sum of joys age and 5 times sierras age is 100

Solution

Let's solve the problem step by step.

Step 1: Define the variables

  • Let Joy's age be xx.
  • Since Joy and Yaritza's ages are consecutive odd integers, Yaritza's age is x+2x + 2.
  • Sierra's age is given as x+4x + 4 (because her age is older than Yaritza's).

Step 2: Translate the problem into an equation

The problem states:

The sum of Joy's age and 5 times Sierra's age is 100.

This can be written as: x+5(x+4)=100x + 5(x + 4) = 100

Step 3: Simplify the equation

Expand and simplify: x+5(x+4)=100x + 5(x + 4) = 100 x+5x+20=100x + 5x + 20 = 100 6x+20=1006x + 20 = 100

Step 4: Solve for xx

Subtract 20 from both sides: 6x=806x = 80

Divide by 6: x=806=13.33x = \frac{80}{6} = 13.33

It seems there may have been an inconsistency in the problem formulation (perhaps Sierra's relationship to Joy or Yaritza was described differently than intended). Could you clarify further, or let me check again for assumptions?

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Integer Sequences

Formulas

Equation of the form x + 5(x + 4) = 100

Theorems

Basic properties of algebraic equations

Suitable Grade Level

Grades 7-9