https://file.aiquickdraw.com/mathbot/file/1728451242428c13vlqvn.jpg

Let's solve the two equations shown in the image.

### Equation 8:
\[
b + 2 = 8 - 2b
\]

Step-by-step solution:
1. Add \( 2b \) to both sides to move all the \( b \)-terms to the left side:
\[
b + 2b + 2 = 8
\]
\[
3b + 2 = 8
\]

2. Subtract 2 from both sides:
\[
3b = 6
\]

3. Divide by 3 to solve for \( b \):
\[
b = 2
\]

### Equation 10:
\[
5n - 1 = 6n - 7
\]

Step-by-step solution:
1. Subtract \( 5n \) from both sides to bring all the \( n \)-terms to the right side:
\[
-1 = n - 7
\]

2. Add 7 to both sides:
\[
6 = n
\]

### Final Solutions:
- For equation 8: \( b = 2 \)
- For equation 10: \( n = 6 \)

Let me know if you'd like further details or if you have any questions!

Here are five related questions for practice:
1. Solve \( 2x + 5 = 7 - x \).
2. If \( 4y - 3 = 2y + 9 \), what is \( y \)?
3. Solve for \( z \) in \( 3z + 2 = 8z - 10 \).
4. What is \( x \) if \( 7x - 4 = 3x + 12 \)?
5. Solve \( 5m + 2 = 4m - 8 \).

**Tip:** Always aim to isolate the variable by performing the same operation on both sides of the equation.

Solve the following equations: b + 2 = 8 - 2b and 5n - 1 = 6n - 7.

In this lesson, learn how to solve two linear equations step-by-step. For the first equation, b + 2 = 8 - 2b, the solution for b is found using basic algebraic methods. For the second equation, 5n - 1 = 6n - 7, we solve for n by isolating the variable. Perfect for students in Grades 7-9.

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