Let's solve the equation \( 2b - 9 = 8b + 9 \).

### Step 1: Move all terms involving \( b \) to one side
Subtract \( 8b \) from both sides:
\[
2b - 8b - 9 = 8b - 8b + 9
\]
\[
-6b - 9 = 9
\]

### Step 2: Move constant terms to the other side
Add 9 to both sides:
\[
-6b - 9 + 9 = 9 + 9
\]
\[
-6b = 18
\]

### Step 3: Solve for \( b \)
Divide both sides by \( -6 \):
\[
b = \frac{18}{-6} = -3
\]

### Final Answer:
\[
b = -3
\]

Do you want further details or have any questions?

Here are 5 related questions to expand your understanding:
1. How do you solve linear equations with variables on both sides?
2. What happens if the coefficients of \( b \) are fractions?
3. How can you check if your solution is correct?
4. What if the equation was \( 2b - 9 = 8b - 9 \)?
5. How do you solve an equation if there are parentheses involved, like \( 2(b - 4) = 8b + 9 \)?

**Tip:** Always check your solution by substituting the value of the variable back into the original equation.

This page provides a detailed, step-by-step solution to solving the linear equation 2b - 9 = 8b + 9. Learn how to move variables to one side and isolate the variable to find the solution b = -3. Suitable for students in Grades 6-8.

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