https://file.aiquickdraw.com/mathbot/file/1729773161238sjty8q50.jpg

Let's solve the given equations one by one.

### a) \( 3x - 1 = 5 \)

**Step 1:** Add 1 to both sides:
\[
3x = 6
\]

**Step 2:** Divide by 3:
\[
x = 2
\]

### d) \( 6a - 5 = 25 \)

**Step 1:** Add 5 to both sides:
\[
6a = 30
\]

**Step 2:** Divide by 6:
\[
a = 5
\]

### g) \( \frac{x - 3}{5} = 4 \)

**Step 1:** Multiply both sides by 5:
\[
x - 3 = 20
\]

**Step 2:** Add 3 to both sides:
\[
x = 23
\]

Let me know if you'd like more details or have any questions.

Here are five related questions to deepen understanding:

1. How would you solve \(4x - 2 = 10\)?
2. What is the general method to solve linear equations?
3. Can you solve \(7y + 3 = 24\)?
4. What happens if the variable term has a negative coefficient?
5. Can you solve \( \frac{x + 2}{4} = 3 \)?

**Tip:** Always reverse the operations applied to the variable when solving for it (e.g., if subtracting, add; if multiplying, divide).

Solve the following equations: a) 3x - 1 = 5, d) 6a - 5 = 25, g) (x - 3)/5 = 4

This page covers the step-by-step solutions for solving linear equations such as 3x - 1 = 5, 6a - 5 = 25, and (x - 3)/5 = 4. Learn key algebraic techniques, including how to isolate variables and use the properties of equality. Suitable for students in Grades 6-8.

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