Let's solve the equation step by step:

Given equation: $2x + 6x + 12 = 3x + x$

1. Combine like terms on each side of the equation:

   On the left side: $2x + 6x = 8x$ So, the equation becomes: $8x + 12 = 3x + x$

   On the right side: $3x + x = 4x$ So, the equation becomes: $8x + 12 = 4x$

2. Move the variable terms to one side:

   Subtract $4x$ from both sides: $8x - 4x + 12 = 4x - 4x$ Simplifying this: $4x + 12 = 0$

3. Isolate the variable:

   Subtract 12 from both sides: $4x = -12$

   Divide both sides by 4: $x = -3$

So, the solution is $x = -3$.

Would you like more details, or do you have any questions?

Here are 5 related questions to further explore this topic:

1. How would you solve a quadratic equation like $2x^2 + 3x + 1 = 0$?
2. What happens if the equation has no real solutions?
3. How do you solve an equation with fractions, such as $\frac{2x}{3} + 4 = x - \frac{5}{2}$?
4. How can you solve a system of linear equations?
5. How does the solution of the equation change if the equation is $2x + 6x + 12 = 3x + 2x$?

Tip: When solving equations, always combine like terms first to simplify the process.