To solve the equation \( x - 2 + y = 1 \), follow these steps:

1. **Isolate one variable**: Let's isolate \( y \).
   \[
   y = 1 - x + 2
   \]
   Simplify the right side:
   \[
   y = 3 - x
   \]

So, the equation simplifies to:
\[
y = 3 - x
\]

This represents a linear relationship between \( x \) and \( y \), where for any value of \( x \), you can find the corresponding value of \( y \).

Would you like further details on this, or do you have any questions?

Here are 5 related questions for further practice:
1. If \( x = 2 \), what is the value of \( y \)?
2. What is the slope of the line represented by \( y = 3 - x \)?
3. How would you write the equation \( x - 2 + y = 1 \) in slope-intercept form?
4. Can you graph the line \( y = 3 - x \)?
5. What happens to \( y \) if \( x \) increases by 1?

**Tip:** The slope of a linear equation in the form \( y = mx + b \) is the coefficient of \( x \).

Learn how to solve the linear equation X - 2 + y = 1 with a step-by-step solution. This problem explores algebraic concepts, including linear equations and slope-intercept form, suitable for students in Grades 6-8.

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