It seems you have provided the following equation:

\[
b - 19 = 23
\]

To solve for \( b \), we will isolate it by adding 19 to both sides of the equation:

\[
b - 19 + 19 = 23 + 19
\]

Simplifying the right-hand side:

\[
b = 42
\]

Thus, the value of \( b \) is:

\[
b = 42
\]

Would you like more details or further explanations?

Here are some related questions to practice:

1. Solve for \( x \): \( x - 25 = 30 \)
2. Solve for \( y \): \( y + 15 = 50 \)
3. Solve for \( z \): \( 2z - 10 = 40 \)
4. If \( a - 12 = 18 \), what is the value of \( a \)?
5. Solve for \( c \): \( 3c - 5 = 10 \)

**Tip:** When solving for a variable, aim to isolate the variable on one side of the equation by performing inverse operations.

Learn how to solve the linear equation b − 19 = 23 with a simple step-by-step explanation. This problem involves key algebraic concepts, including the use of inverse operations to isolate variables. Suitable for students in Grades 6-8.

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