a–2=3+6a3
 
Enter your answer in the box.

*a* = 

Let's solve the equation:

\[
a - 2 = 3 + 6a
\]

### Step 1: Move the terms involving \( a \) to one side of the equation.

Subtract \( 6a \) from both sides:

\[
a - 6a - 2 = 3
\]

### Step 2: Simplify the equation.

Combine like terms on the left side:

\[
-5a - 2 = 3
\]

### Step 3: Move the constant term to the other side.

Add 2 to both sides:

\[
-5a = 3 + 2
\]

\[
-5a = 5
\]

### Step 4: Solve for \( a \).

Divide both sides by \( -5 \):

\[
a = \frac{5}{-5} = -1
\]

### Final Answer:
\[
a = -1
\]

Would you like more details or have any questions?

Here are some related questions:
1. What happens if we subtract a different constant from both sides?
2. Can we solve equations with variables on both sides differently?
3. How do we check the solution of an equation?
4. Can we graph the equation to visualize its solution?
5. What are some examples of equations where \( a \) has a different value?

**Tip:** Always check your solution by plugging it back into the original equation!

a - 2 = 3 + 6a
Enter your answer in the box. *a* = 

Learn how to solve the linear equation a - 2 = 3 + 6a with a clear step-by-step solution. This problem demonstrates key algebraic techniques for simplifying and solving equations with variables on both sides. Ideal for students in Grades 6-8.

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