https://file.aiquickdraw.com/mathbot/file/1730446838477lvp0lf3j.jpg

The example in the image demonstrates how to solve a linear equation step-by-step. Here’s the breakdown:

1. **Given Equation**: \( 2a + 4 = 4a - 2 \)

2. **Step 1**: Move all terms involving \( a \) to one side by subtracting \( 2a \) from both sides:
   \[
   2a + 4 - 2a = 4a - 2 - 2a
   \]
   This simplifies to:
   \[
   4 = 2a - 2
   \]

3. **Step 2**: Move constant terms to the other side by adding 2 to both sides:
   \[
   4 + 2 = 2a - 2 + 2
   \]
   This simplifies to:
   \[
   6 = 2a
   \]

4. **Step 3**: Solve for \( a \) by dividing both sides by 2:
   \[
   a = \frac{6}{2} = 3
   \]

5. **Verification**: Substitute \( a = 3 \) back into the original equation to check the solution:
   - Left side: \( 2(3) + 4 = 6 + 4 = 10 \)
   - Right side: \( 4(3) - 2 = 12 - 2 = 10 \)
   
   Since both sides are equal, \( a = 3 \) is the correct solution.

Would you like more details on any specific step?

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Here are some related questions you might consider:

1. How do you solve equations with variables on both sides?
2. What happens if you end up with a statement that is always true (e.g., \(0 = 0\))?
3. What do you do if you end up with a statement that is always false (e.g., \(0 = 5\))?
4. How do you handle equations with fractions?
5. How can you verify solutions to equations?

**Tip**: Always check your solution by substituting it back into the original equation to ensure both sides match.

Solve the following equation: 2a + 4 = 4a - 2

Learn how to solve the linear equation 2a + 4 = 4a - 2 with a step-by-step solution. This example demonstrates moving terms with variables to one side and constants to the other. Suitable for students in Grades 6-8.

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