To solve the equation \( 4u + 3u = 28 \), follow these steps:

1. Combine like terms:
   \[
   4u + 3u = 7u
   \]
   So the equation becomes:
   \[
   7u = 28
   \]

2. Divide both sides of the equation by 7 to isolate \( u \):
   \[
   u = \frac{28}{7} = 4
   \]

Thus, the solution is \( u = 4 \).

Would you like any further details or have any questions?

Here are 5 related questions to expand on this concept:
1. What happens if the equation was \( 5u + 2u = 35 \)?
2. How would you solve \( 4u + 3u = 28 + u \)?
3. What if the equation was \( 7u = 49 \), how would you solve it?
4. Can you solve \( 4u + 3v = 28 \) for \( u \) in terms of \( v \)?
5. How would you check if \( u = 4 \) is the correct solution for this equation?

**Tip:** Always simplify equations by combining like terms before solving.

This tutorial explains how to solve the linear equation 4u + 3u = 28 by combining like terms and isolating the variable. It covers key algebraic techniques and is designed for students in Grades 6-8.

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