Let's solve the equation: 

\[
-3y + 2 = -10y + 30
\]

### Step 1: Move all terms involving \( y \) to one side
Add \( 10y \) to both sides to get:

\[
-3y + 10y + 2 = 30
\]

Simplifying:

\[
7y + 2 = 30
\]

### Step 2: Move the constant to the other side
Subtract 2 from both sides:

\[
7y = 30 - 2
\]

\[
7y = 28
\]

### Step 3: Solve for \( y \)
Divide both sides by 7:

\[
y = \frac{28}{7}
\]

\[
y = 4
\]

So, the solution is \( y = 4 \).

Would you like further details or have any questions?

Here are some related questions:
1. What happens when all variables cancel out in an equation?
2. How can you solve an equation with fractions?
3. How do you check if your solution to an equation is correct?
4. What is the process for solving systems of linear equations?
5. How does factoring help in solving quadratic equations?

**Tip**: Always double-check your solution by plugging it back into the original equation.

Learn how to solve the linear equation -3y + 2 = -10y + 30 with a detailed step-by-step guide. This problem covers key algebraic concepts, including solving linear equations and properties of equality. Suitable for students in Grades 6-8.

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