The equation in the image is:

$\frac{3}{4}(x + 8) = 9$

To solve for $x$:

1. Multiply both sides by 4 to eliminate the denominator:

$3(x + 8) = 9 \times 4$

$3(x + 8) = 36$

2. Divide both sides by 3 to isolate the $x + 8$ term:

$x + 8 = \frac{36}{3}$

$x + 8 = 12$

3. Subtract 8 from both sides to solve for $x$:

$x = 12 - 8$

$x = 4$

Final answer:

$x = 4$

Would you like any further details or have any questions?

Here are five related questions for further practice:

1. Solve $\frac{2}{3}(x - 5) = 10$.
2. Solve $\frac{5}{6}(2x + 3) = 15$.
3. What happens if $\frac{3}{4}(x + 8) = 12$? How does that change $x$?
4. Solve $\frac{7}{5}(x - 9) = 14$.
5. Solve $2x + 3 = 9$.

Tip: Always remember to first eliminate any fractions by multiplying both sides of the equation by the denominator!