Math Problem Statement

In the following linear equation, solve for y. The goal is to get y on one side of the equal sign by following the steps: 2x - 3y = 9

Solution

Let's go through the problem step-by-step:

We are given the equation:

2x3y=92x - 3y = 9

The goal is to solve for yy by isolating it on one side of the equation. The instructions ask to fill in the blanks for the steps provided.

Step 1: Subtract ____ from both sides of the equal.

To isolate yy, we first need to get rid of the term involving xx. So, we subtract 2x2x from both sides:

2x3y2x=92x2x - 3y - 2x = 9 - 2x

This simplifies to:

3y=2x+9-3y = -2x + 9

Step 2: Divide both sides by ____.

Now, to fully isolate yy, divide both sides by 3-3 (since yy is multiplied by 3-3):

y=2x+93y = \frac{-2x + 9}{-3}

Simplifying the right-hand side:

y=2x3+93y = \frac{-2x}{-3} + \frac{9}{-3}

y=2x33y = \frac{2x}{3} - 3

Thus, the solution for yy is:

y=2x33y = \frac{2x}{3} - 3

Answer:

  • Step 1: Subtract 2x2x from both sides.
  • Step 2: Divide both sides by 3-3.

Would you like more details, or do you have any questions?

Here are 5 related questions:

  1. What does it mean to isolate a variable in an equation?
  2. How do you know which term to subtract in step 1?
  3. What are the rules for dividing both sides of an equation by a negative number?
  4. How do you graph the equation y=2x33y = \frac{2x}{3} - 3?
  5. What happens if you don’t subtract the right term in the first step?

Tip: Always remember to flip the sign when dividing by a negative number to keep the equation consistent.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

Linear equation form: ax + by = c

Theorems

Basic Algebraic Operations

Suitable Grade Level

Grades 6-8