To solve the equation $2(x - 1) - 3x = 6$:

1. First, expand $2(x - 1)$: $2(x - 1) = 2x - 2$ So, the equation becomes: $2x - 2 - 3x = 6$

2. Combine like terms: $(2x - 3x) - 2 = 6$ $-x - 2 = 6$

3. Isolate $x$ by adding 2 to both sides: $-x = 8$

4. Divide by -1 to solve for $x$: $x = -8$

The correct answer is A) -8.

Would you like more details, or do you have any questions?

Here are some related questions to expand your understanding:

1. What happens if you multiply both sides by a constant at the beginning?
2. How do you check if a solution to an equation is correct?
3. Can you solve similar equations if the terms are fractions instead of integers?
4. What if the equation had terms with higher powers of $x$?
5. How would you solve this equation if it were part of a system of equations?

Tip: Always check your answer by substituting it back into the original equation to verify correctness.