Math Problem Statement

  • 2/3 +2g =-3/2 g+3-2g

Solution

Let's solve the equation step by step:

The given equation is: 23+2g=32g+32g-\frac{2}{3} + 2g = -\frac{3}{2}g + 3 - 2g

Step 1: Combine like terms

On the left-hand side (LHS):

23+2g-\frac{2}{3} + 2g

On the right-hand side (RHS):

32g+32g-\frac{3}{2}g + 3 - 2g

Simplify the RHS: 32g2g+3=32g42g+3=72g+3-\frac{3}{2}g - 2g + 3 = -\frac{3}{2}g - \frac{4}{2}g + 3 = -\frac{7}{2}g + 3

The equation now becomes: 23+2g=72g+3-\frac{2}{3} + 2g = -\frac{7}{2}g + 3

Step 2: Move all terms involving gg to one side and constants to the other

Subtract 2g2g from both sides: 23=72g2g+3-\frac{2}{3} = -\frac{7}{2}g - 2g + 3

Simplify the gg-terms on the RHS: 72g2g=72g42g=112g-\frac{7}{2}g - 2g = -\frac{7}{2}g - \frac{4}{2}g = -\frac{11}{2}g

Now the equation is: 23=112g+3-\frac{2}{3} = -\frac{11}{2}g + 3

Next, subtract 3 from both sides: 233=112g-\frac{2}{3} - 3 = -\frac{11}{2}g

Simplify the constants on the LHS: 233=2393=113-\frac{2}{3} - 3 = -\frac{2}{3} - \frac{9}{3} = -\frac{11}{3}

The equation now becomes: 113=112g-\frac{11}{3} = -\frac{11}{2}g

Step 3: Solve for gg

Divide both sides by 112-\frac{11}{2} (or multiply by the reciprocal): g=113112=113211g = \frac{-\frac{11}{3}}{-\frac{11}{2}} = \frac{11}{3} \cdot \frac{2}{11}

Simplify: g=23g = \frac{2}{3}

Final Answer:

g=23g = \frac{2}{3}


Would you like more details or have any specific questions? 😊

Five Related Questions:

  1. How do you solve equations involving fractions systematically?
  2. Can you explain how to simplify terms with variables and constants?
  3. What is the process for finding the least common denominator (LCD) in equations?
  4. How do you check if a solution is correct for a given equation?
  5. Can such equations be solved graphically, and if so, how?

Tip:

Always simplify fractions as much as possible early in the solution process to avoid unnecessary complexity.

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Math Problem Analysis

Mathematical Concepts

Algebra
Solving Linear Equations
Combining Like Terms
Simplifying Fractions

Formulas

Basic linear equation manipulation
Solving for a variable in a linear equation

Theorems

Linear Equation Solution

Suitable Grade Level

Grades 7-9