To solve the equation $-10x + 2y = -20$ and find the ordered pairs for the table provided, let's break it down:

1. Substitute $x = 0$ into the equation: $-10(0) + 2y = -20$ Simplifying this: $2y = -20$ Now, divide by 2: $y = -10$ So, when $x = 0$, $y = -10$. The ordered pair is $(0, -10)$.

2. Substitute $y = 0$ into the equation: $-10x + 2(0) = -20$ Simplifying this: $-10x = -20$ Now, divide by -10: $x = 2$ So, when $y = 0$, $x = 2$. The ordered pair is $(2, 0)$.

Thus, the table would be filled out as follows:

For the graph, you would plot the points $(0, -10)$ and $(2, 0)$, then draw a straight line passing through these two points.

Would you like more details on graphing, or have any further questions? Here are five questions to deepen understanding:

1. How do you determine the slope of a line from two points?
2. Can you find more points on the line using the slope-intercept form?
3. What is the slope of the line $-10x + 2y = -20$?
4. How can you convert $-10x + 2y = -20$ into slope-intercept form?
5. How would you graph more complex linear equations?

Tip: For graphing lines, it helps to find the intercepts (where the line crosses the x- and y-axes), which we just did by setting $x = 0$ and $y = 0$.