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To solve the equation \(-10x + 2y = -20\) and find the ordered pairs for the table provided, let's break it down:

1. **Substitute \(x = 0\)** into the equation:
   \[
   -10(0) + 2y = -20
   \]
   Simplifying this:
   \[
   2y = -20
   \]
   Now, divide by 2:
   \[
   y = -10
   \]
   So, when \(x = 0\), \(y = -10\). The ordered pair is \((0, -10)\).

2. **Substitute \(y = 0\)** into the equation:
   \[
   -10x + 2(0) = -20
   \]
   Simplifying this:
   \[
   -10x = -20
   \]
   Now, divide by -10:
   \[
   x = 2
   \]
   So, when \(y = 0\), \(x = 2\). The ordered pair is \((2, 0)\).

Thus, the table would be filled out as follows:

| \(x\) | \(y\)  | Ordered Pair |
|:----:|:-----:|:------------:|
|  0   |  -10  |  \((0, -10)\) |
|  2   |   0   |   \((2, 0)\)  |

For the graph, you would plot the points \((0, -10)\) and \((2, 0)\), then draw a straight line passing through these two points.

Would you like more details on graphing, or have any further questions? Here are five questions to deepen understanding:

1. How do you determine the slope of a line from two points?
2. Can you find more points on the line using the slope-intercept form?
3. What is the slope of the line \(-10x + 2y = -20\)?
4. How can you convert \(-10x + 2y = -20\) into slope-intercept form?
5. How would you graph more complex linear equations?

**Tip**: For graphing lines, it helps to find the intercepts (where the line crosses the x- and y-axes), which we just did by setting \(x = 0\) and \(y = 0\).

Solve the equation -10x + 2y = -20 using a graph.

Learn how to solve the linear equation -10x + 2y = -20 by finding the x- and y-intercepts and plotting the graph. This tutorial covers essential algebraic concepts and graphing techniques, suitable for students in Grades 8-10.

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