Math Problem Statement
(a) lim h→0 √4+h−2 h (b) lim x→4 x2−16 √x−2 solove using algebraic simplification
Solution
Let's solve both limits using algebraic simplification.
(a)
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Multiply by the conjugate: To simplify, we multiply both the numerator and the denominator by the conjugate of the numerator, . This results in: Simplifying the numerator:
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Cancel out the :
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Substitute :
Thus, the solution for (a) is:
(b)
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Factor the numerator: So the limit becomes:
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Multiply by the conjugate of the denominator: To handle the in the denominator, we multiply both the numerator and denominator by the conjugate, : Simplifying the denominator:
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Cancel out the terms:
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Substitute :
Thus, the solution for (b) is:
Let me know if you want further details or have any questions. Here are 5 related questions to extend this topic:
- How do you find limits involving indeterminate forms?
- What are some common techniques for simplifying radical expressions?
- How do conjugates help in rationalizing denominators?
- What is L'Hopital's Rule, and how does it apply to limits?
- Can you explain the concept of continuity and its relationship to limits?
Tip: Multiplying by the conjugate is a powerful tool to simplify expressions involving square roots.
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Math Problem Analysis
Mathematical Concepts
Limits
Algebraic Simplification
Conjugates
Radicals
Formulas
lim h→0 (√(4+h) - 2) / h
lim x→4 (x² - 16) / (√x - 2)
Theorems
Conjugate Multiplication Theorem
Difference of Squares
Limit Substitution Rule
Suitable Grade Level
Grades 11-12
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