The inequality you have is:

$-x + y < -3$

Let's solve this inequality for $y$ in terms of $x$:

Step 1: Isolate $y$

First, we need to move the $-x$ to the other side of the inequality.

$y < x - 3$

Final Answer:

So, the inequality becomes:

$y < x - 3$

This tells us that for any value of $x$, $y$ must be less than $x - 3$.

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Do you need further explanation on how to graph this inequality, or any other clarification? Here are some related questions:

1. How do you graph the inequality $y < x - 3$?
2. What happens if the inequality was $y \leq x - 3$?
3. How do you solve an inequality with multiple variables, such as $2x - 3y > 4$?
4. Can inequalities have no solution? What would that look like?
5. What is the difference between strict inequalities (like $<$) and non-strict inequalities (like $\leq$)?

Tip: Remember, when graphing inequalities like $y < x - 3$, use a dashed line for the boundary $y = x - 3$ since the inequality is strict ($<$) and doesn't include the line itself.