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Let's break down and solve the inequality given in the problem.

The sentence says: "Nine more than twice a number is less than negative fifteen."

We can represent this mathematically as:

\[
2x + 9 < -15
\]

### Step-by-step solution:

1. **Subtract 9 from both sides** to isolate the term with the variable:
   \[
   2x + 9 - 9 < -15 - 9
   \]
   Simplifying both sides:
   \[
   2x < -24
   \]

2. **Divide by 2** on both sides to solve for \(x\):
   \[
   \frac{2x}{2} < \frac{-24}{2}
   \]
   Simplifying:
   \[
   x < -12
   \]

### Final Answer:
The solution to the inequality is:
\[
x < -12
\]

Would you like more details or have any questions? Here are 5 related questions you might find helpful:

1. How do we solve inequalities with addition and subtraction?
2. What happens when we divide or multiply inequalities by negative numbers?
3. How do we represent inequality solutions on a number line?
4. What’s the difference between solving inequalities and solving equations?
5. How can we apply this method to more complex inequalities?

**Tip:** When multiplying or dividing both sides of an inequality by a negative number, remember to reverse the inequality symbol!

Nine more than twice a number is less than negative fifteen. Solve the inequality for the unknown number.

Learn how to solve the inequality where nine more than twice a number is less than negative fifteen. This problem involves solving inequalities through subtraction and division, suitable for students in Grades 7-9.

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