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The problem asks to solve for \( h \) in the formula for the volume of a cone:

\[
V = \frac{1}{3} B h
\]

Where:
- \( V \) is the volume of the cone,
- \( B \) is the area of the base (which is usually \( B = \pi r^2 \) for a circular base),
- \( h \) is the height of the cone.

### To solve for \( h \):
1. Start with the given formula:
   \[
   V = \frac{1}{3} B h
   \]
   
2. Multiply both sides by 3 to eliminate the fraction:
   \[
   3V = B h
   \]

3. Finally, divide both sides by \( B \) to isolate \( h \):
   \[
   h = \frac{3V}{B}
   \]

So the height \( h \) in terms of the volume \( V \) and base area \( B \) is:
\[
h = \frac{3V}{B}
\]

Would you like further clarification or additional examples?

### Related questions:
1. How do you calculate the base area \( B \) of a cone with a circular base?
2. What happens to the height if the volume of the cone is doubled?
3. How can you calculate the volume of a cone given the radius and height?
4. If you know the slant height of a cone, how can you find its vertical height?
5. How does changing the radius affect the volume of the cone?

### Tip:
Remember that for cones with circular bases, the base area \( B = \pi r^2 \), where \( r \) is the radius of the base.

The formula V = 1/3 BH can be used to find the volume of a cone. Solve the formula for h.

Discover how to isolate and solve for the height (h) in the cone's volume formula, V = 1/3 Bh. This explanation provides step-by-step algebraic manipulation suitable for middle school to high school students.

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