Options are a 25, 65 B 60, 30 C 65, 25 D40, 50.

Let's re-examine the problem considering the provided options.

### Step 1: Recall the key relationships
- \( AB \parallel CD \) implies that corresponding angles and alternate interior angles can be used.
- \( \angle ACD = 150^\circ \).
- \( \angle CAB = 90^\circ \).

### Step 2: Re-calculate angle \( x \)
\( x \) is the supplementary angle to \( 150^\circ \) because \( \angle ACD \) is on a straight line. Thus:
\[
x = 180^\circ - 150^\circ = 30^\circ
\]

### Step 3: Re-calculate angle \( y \)
Using the triangle \( \triangle ABC \):
\[
\angle CAB + \angle ABC + \angle BCA = 180^\circ
\]
Given that \( \angle CAB = 90^\circ \) and \( x = 30^\circ \), then:
\[
90^\circ + y + 30^\circ = 180^\circ
\]
\[
y = 180^\circ - 120^\circ = 60^\circ
\]

### Conclusion:
- \( x = 30^\circ \)
- \( y = 60^\circ \)

Therefore, the correct option is **B) 60, 30**.

Would you like further details or have any other questions?

### Related Questions:
1. Why is \( \angle CAB \) considered as 90° in this scenario?
2. How would you solve the problem if the angle \( \angle ACD \) were not given?
3. Can the angle \( y \) ever be larger than \( 90^\circ \) in this figure?
4. What is the significance of the parallel lines in determining the angles?
5. How do corresponding angles help in solving geometry problems involving parallel lines?

### Tip:
When working with triangles and parallel lines, always ensure to double-check the relationships between angles, particularly when supplementary or complementary angles are involved.

Explore how to solve a geometry problem involving angles and parallel lines. Understand the properties of angles in triangles and parallel lines to find the correct solution. Suitable for high school students studying geometry.

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