Math Problem Statement

Find unknown angles in geometry problems and classify angles as acute, obtuse, right, or straight.

Solution

Let's solve the problems in the image you've uploaded:

1. Given:

  • mABD=40m\angle ABD = 40^\circ
  • mABC=78m\angle ABC = 78^\circ

Find mDBCm\angle DBC:

  • We know that mABC=mABD+mDBCm\angle ABC = m\angle ABD + m\angle DBC.
  • So, 78=40+mDBC78^\circ = 40^\circ + m\angle DBC.
  • Solving for mDBCm\angle DBC, we get mDBC=7840=38m\angle DBC = 78^\circ - 40^\circ = 38^\circ.

2. Given:

  • mABD=40m\angle ABD = 40^\circ
  • mDBC=36m\angle DBC = 36^\circ

Find mABCm\angle ABC:

  • We know that mABC=mABD+mDBCm\angle ABC = m\angle ABD + m\angle DBC.
  • So, mABC=40+36=76m\angle ABC = 40^\circ + 36^\circ = 76^\circ.

3. Given:

  • mWXZ=57m\angle WXZ = 57^\circ
  • mWXY=123m\angle WXY = 123^\circ

Find mZXYm\angle ZXY:

  • We know that mWXY=mWXZ+mZXYm\angle WXY = m\angle WXZ + m\angle ZXY.
  • So, 123=57+mZXY123^\circ = 57^\circ + m\angle ZXY.
  • Solving for mZXYm\angle ZXY, we get mZXY=12357=66m\angle ZXY = 123^\circ - 57^\circ = 66^\circ.

4. Given:

  • mZXY=54m\angle ZXY = 54^\circ
  • mWXZ=60m\angle WXZ = 60^\circ

Find mWXYm\angle WXY:

  • We know that mWXY=mWXZ+mZXYm\angle WXY = m\angle WXZ + m\angle ZXY.
  • So, mWXY=60+54=114m\angle WXY = 60^\circ + 54^\circ = 114^\circ.

5. Given:

  • mLMN=135m\angle LMN = 135^\circ
  • mLMV=45x1m\angle LMV = 45x - 1^\circ
  • mVMN=23xm\angle VMN = 23x

Find xx:

  • The three angles form a straight line, so their sum should be 180180^\circ.
  • Set up the equation: 135+(45x1)+23x=180.135^\circ + (45x - 1^\circ) + 23x = 180^\circ.
  • Simplifying: 135+45x1+23x=180,135 + 45x - 1 + 23x = 180, 134+68x=180,134 + 68x = 180, 68x=46,68x = 46, x=4668=23340.676.x = \frac{46}{68} = \frac{23}{34} \approx 0.676.

6. Given:

  • mGFE=157m\angle GFE = 157^\circ
  • mNFE=14x+3m\angle NFE = 14x + 3^\circ
  • mGFN=4x+10m\angle GFN = 4x + 10^\circ

Find xx:

  • The sum of the three angles should be 180180^\circ because they form a straight line.
  • Set up the equation: 157+(14x+3)+(4x+10)=180,157^\circ + (14x + 3^\circ) + (4x + 10^\circ) = 180^\circ, 157+14x+3+4x+10=180,157 + 14x + 3 + 4x + 10 = 180, 170+18x=180,170 + 18x = 180, 18x=10,18x = 10, x=1018=590.556.x = \frac{10}{18} = \frac{5}{9} \approx 0.556.

7. Classify the angles as acute, obtuse, right, or straight:

  • DOG\angle DOG: Appears obtuse (greater than 9090^\circ).
  • DOS\angle DOS: Appears acute (less than 9090^\circ).
  • DSG\angle DSG: Appears obtuse.
  • GOS\angle GOS: Appears acute.

Would you like more details on any specific step or have any questions?

Here are 5 related questions to think about:

  1. How would you classify angles based on their measurements?
  2. How can you find an unknown angle in a triangle given two other angles?
  3. What is the relationship between adjacent angles on a straight line?
  4. How do you solve for xx in an equation with angles forming a straight line?
  5. What is the sum of interior angles of a polygon?

Tip: Always remember that the sum of angles on a straight line is 180180^\circ.

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Math Problem Analysis

Mathematical Concepts

Angle relationships
Supplementary angles
Geometry
Algebra

Formulas

Sum of angles on a straight line = 180°
Angle sum property in triangles

Theorems

Angle Addition Postulate
Supplementary Angles Theorem

Suitable Grade Level

Grades 6-8