Math Problem Statement

Use the graphs of 𝑓 and 𝑔 to find and simplify the indicated values.

Click on the graph to view the enlarged graph

(𝑓+𝑔)(3)=

functionsequation editor (π‘”βˆ’π‘“)(βˆ’2)=

functionsequation editor (𝑓𝑔)(5)=

functionsequation editor (𝑔𝑓)(βˆ’4)=

Use the graphs of f(x) and g(x) to find and simplify the indicated values: (f+g)(3), (g-f)(-2), (f*g)(5), (g*f)(-4).

Solution

To solve the given problems using the provided graph of the functions f(x)f(x) and g(x)g(x), let's break down each expression:

1. (f+g)(3)(f + g)(3)

This is asking for the sum of the values of f(x)f(x) and g(x)g(x) when x=3x = 3.

  • From the graph, f(3)f(3) is the red point at x=3x = 3, which corresponds to the value 2.
  • Similarly, g(3)g(3) is the blue point at x=3x = 3, which corresponds to the value -3.

Thus, (f+g)(3)=f(3)+g(3)=2+(βˆ’3)=βˆ’1(f + g)(3) = f(3) + g(3) = 2 + (-3) = -1.

2. (gβˆ’f)(βˆ’2)(g - f)(-2)

This is asking for the difference between the values of g(x)g(x) and f(x)f(x) when x=βˆ’2x = -2.

  • From the graph, g(βˆ’2)g(-2) is the blue point at x=βˆ’2x = -2, which corresponds to the value 2.
  • f(βˆ’2)f(-2) is the red point at x=βˆ’2x = -2, which corresponds to the value 3.

Thus, (gβˆ’f)(βˆ’2)=g(βˆ’2)βˆ’f(βˆ’2)=2βˆ’3=βˆ’1(g - f)(-2) = g(-2) - f(-2) = 2 - 3 = -1.

3. (fβ‹…g)(5)(f \cdot g)(5)

This is asking for the product of the values of f(x)f(x) and g(x)g(x) when x=5x = 5.

  • From the graph, f(5)f(5) is the red point at x=5x = 5, which corresponds to the value -2.
  • g(5)g(5) is the blue point at x=5x = 5, which corresponds to the value -4.

Thus, (fβ‹…g)(5)=f(5)β‹…g(5)=(βˆ’2)β‹…(βˆ’4)=8(f \cdot g)(5) = f(5) \cdot g(5) = (-2) \cdot (-4) = 8.

4. (gβ‹…f)(βˆ’4)(g \cdot f)(-4)

This is asking for the product of the values of g(x)g(x) and f(x)f(x) when x=βˆ’4x = -4.

  • From the graph, g(βˆ’4)g(-4) is the blue point at x=βˆ’4x = -4, which corresponds to the value -3.
  • f(βˆ’4)f(-4) is the red point at x=βˆ’4x = -4, which corresponds to the value 4.

Thus, (gβ‹…f)(βˆ’4)=g(βˆ’4)β‹…f(βˆ’4)=(βˆ’3)β‹…4=βˆ’12(g \cdot f)(-4) = g(-4) \cdot f(-4) = (-3) \cdot 4 = -12.

Summary of results:

  1. (f+g)(3)=βˆ’1(f + g)(3) = -1
  2. (gβˆ’f)(βˆ’2)=βˆ’1(g - f)(-2) = -1
  3. (fβ‹…g)(5)=8(f \cdot g)(5) = 8
  4. (gβ‹…f)(βˆ’4)=βˆ’12(g \cdot f)(-4) = -12

Would you like more details or have any other questions?

Here are 5 relative questions to deepen understanding:

  1. What is the value of (f+g)(βˆ’1)(f + g)(-1)?
  2. How do you interpret the intersection point of f(x)f(x) and g(x)g(x)?
  3. Can you find (gβ‹…f)(1)(g \cdot f)(1)?
  4. What happens when (fβˆ’g)(0)(f - g)(0)?
  5. How would you calculate f(4)+g(4)f(4) + g(4)?

Tip: Always check both the function's x-coordinate and y-coordinate values carefully before solving function-related problems from graphs.

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Math Problem Analysis

Mathematical Concepts

Graphing Functions
Addition of Functions
Subtraction of Functions
Multiplication of Functions

Formulas

(f + g)(x) = f(x) + g(x)
(g - f)(x) = g(x) - f(x)
(f * g)(x) = f(x) * g(x)
(g * f)(x) = g(x) * f(x)

Theorems

-

Suitable Grade Level

Grades 9-11