Math Problem Statement

Use the diagram to solve for x: x = ___. Then use your answer to solve for m∠JKL: m∠JKL = ___.

Solution

The problem involves using properties of parallel lines and angles. From the diagram, we can see that two lines are parallel (indicated by the arrows), and they intersect with a transversal that creates angles.

The key relationship we need is the property of corresponding angles. Corresponding angles are equal when two lines are parallel and intersected by a transversal.

We have the following:

  • Angle at JJ is represented as 7x147x - 14^\circ.
  • Angle at KK is represented as 4x+74x + 7^\circ.

Since the lines are parallel, the angles at JJ and KK are corresponding angles. Therefore, we can set up the equation:

7x14=4x+77x - 14 = 4x + 7

Now, let's solve for xx:

  1. Subtract 4x4x from both sides: 3x14=73x - 14 = 7

  2. Add 14 to both sides: 3x=213x = 21

  3. Divide by 3: x=7x = 7

Now that we have x=7x = 7, we can substitute this value back into either angle expression to find the measure of angle JKL\angle JKL. Let's use the expression 4x+74x + 7^\circ for K\angle K:

mJKL=4(7)+7=28+7=35m \angle JKL = 4(7) + 7 = 28 + 7 = 35^\circ

So, mJKL=35m \angle JKL = 35^\circ.

Summary:

  • x=7x = 7
  • mJKL=35m \angle JKL = 35^\circ

Would you like further explanations or help with any other questions? Here are a few related questions:

  1. How do we identify corresponding angles in other geometric figures?
  2. What is the difference between corresponding and alternate interior angles?
  3. What would happen if the lines were not parallel in this situation?
  4. How do properties of parallel lines help us solve for unknowns in geometry?
  5. Can we apply this method to solve for angles in polygons?

Tip: Always check if the lines are parallel before assuming angle relationships.

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Math Problem Analysis

Mathematical Concepts

Geometry
Parallel Lines
Corresponding Angles
Algebra

Formulas

Corresponding Angles Property
Linear Equation Solving

Theorems

Corresponding Angles Postulate

Suitable Grade Level

Grades 7-9