Math Problem Statement

If \( \frac{c - d}{c + d} = 2 \) and \( d = 1 \), what is the value of \( c \)?

Solution

The problem asks us to find the value of cc given that:

cdc+d=2andd=1.\frac{c - d}{c + d} = 2 \quad \text{and} \quad d = 1.

Let's solve this step by step:

Step 1: Substitute d=1d = 1

Substitute d=1d = 1 into the equation:

c1c+1=2.\frac{c - 1}{c + 1} = 2.

Step 2: Cross-multiply to solve for cc

Cross-multiply to eliminate the fraction:

c1=2(c+1).c - 1 = 2(c + 1).

Step 3: Expand and simplify

Expand the right side:

c1=2c+2.c - 1 = 2c + 2.

Bring terms involving cc to one side:

12=c.-1 - 2 = c.

c=3.c = -3.

Final Answer:

The value of cc is 3\boxed{-3}.

Would you like a detailed explanation or have any questions?

Related Questions:

  1. How do you solve equations involving fractions like cdc+d=2\frac{c - d}{c + d} = 2?
  2. What is cross-multiplication, and when is it used?
  3. How would the solution change if dd had a different value?
  4. How can you check your answer when solving equations?
  5. What are common mistakes to avoid when solving rational equations?

Tip:

When solving equations involving fractions, always consider cross-multiplying as a way to eliminate the fraction, making it easier to solve for the unknown variable.

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Math Problem Analysis

Mathematical Concepts

Algebra
Rational Equations

Formulas

Cross-multiplication
\( \frac{c - d}{c + d} = 2 \)

Theorems

Basic Algebraic Operations

Suitable Grade Level

Grades 8-10