Math Problem Statement

Given that m∠AOB = 5w + 4, m∠DOE = 9w - 12, and ∠AOE is a straight angle, find the value of m∠BOC.

Solution

In the image, we are given an angle diagram with the following information:

  • mAOB=5w+4m \angle AOB = 5w + 4
  • mDOE=9w12m \angle DOE = 9w - 12
  • AOE\angle AOE is a straight angle, which means mAOE=180m \angle AOE = 180^\circ.
  • We are tasked with finding mBOCm \angle BOC.

Step-by-step solution:

  1. Since AOE\angle AOE is a straight angle, we know: mAOB+mDOE=180m \angle AOB + m \angle DOE = 180^\circ Substituting the given expressions for mAOBm \angle AOB and mDOEm \angle DOE: (5w+4)+(9w12)=180(5w + 4) + (9w - 12) = 180

  2. Simplify the equation: 5w+9w+412=1805w + 9w + 4 - 12 = 180 14w8=18014w - 8 = 180

  3. Solve for ww: 14w=18814w = 188 w=18814=13.43w = \frac{188}{14} = 13.43

  4. Now, to find mBOCm \angle BOC, we observe that: mBOC=mAOBm \angle BOC = m \angle AOB Since mAOB=5w+4m \angle AOB = 5w + 4, substitute w=13.43w = 13.43 into the expression: mBOC=5(13.43)+4=67.15+4=71.15m \angle BOC = 5(13.43) + 4 = 67.15 + 4 = 71.15^\circ

Thus, mBOC71.15m \angle BOC \approx 71.15^\circ.


Do you need further details or have any questions?

Here are 5 related questions to consider:

  1. What are complementary angles, and do they apply here?
  2. How do you solve for angles in a triangle given their sum?
  3. What is the difference between an acute and obtuse angle?
  4. How do linear pairs of angles relate to this problem?
  5. Can you solve for angles when only supplementary information is given?

Tip: Always verify angle sums when dealing with straight angles or triangles to check if the solution is consistent.

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Math Problem Analysis

Mathematical Concepts

Geometry
Algebra
Linear Pair of Angles
Supplementary Angles

Formulas

m∠AOB + m∠DOE = 180°
m∠BOC = m∠AOB

Theorems

Straight Angle Theorem
Supplementary Angles Theorem

Suitable Grade Level

Grades 8-10