Math Problem Statement

the product of positive numbers A and B is 1008.A is 7 times of B.Fine the value of A

Solution

We are given the following conditions:

  • The product of positive numbers AA and BB is 1008, i.e., A×B=1008A \times B = 1008
  • AA is 7 times BB, i.e., A=7BA = 7B

Step 1: Substitute A=7BA = 7B into the product equation.

Substituting A=7BA = 7B into the equation A×B=1008A \times B = 1008: 7B×B=10087B \times B = 1008 7B2=10087B^2 = 1008

Step 2: Solve for BB.

Now, divide both sides of the equation by 7 to solve for B2B^2: B2=10087B^2 = \frac{1008}{7} B2=144B^2 = 144

Taking the square root of both sides: B=144=12B = \sqrt{144} = 12

Step 3: Find AA.

Now that we know B=12B = 12, we can substitute this into the equation A=7BA = 7B to find AA: A=7×12=84A = 7 \times 12 = 84

Thus, the value of AA is 84\boxed{84}.


Would you like further details on this solution or have any questions? Here are some related questions:

  1. What if the relationship between AA and BB was different (e.g., A=5BA = 5B)? How would you solve it?
  2. How can we check that the values of AA and BB satisfy the original product equation?
  3. What happens if one of the numbers, say AA, is negative? How would the solution change?
  4. Can this type of problem be extended to more than two variables?
  5. How would you solve this problem if we were also given that the sum A+B=100A + B = 100?

Tip: Always substitute given relationships into the equation first, as this can simplify solving the problem significantly.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Relationships
Quadratic Equations

Formulas

A × B = 1008
A = 7B

Theorems

Substitution method
Square roots

Suitable Grade Level

Grades 7-9