Math Problem Statement
Solve y' = xy + 3y − 2x − 6
Solution
The given first-order differential equation is:
Step 1: Express in Standard Form
Rewriting it in the form:
This is a first-order linear differential equation of the form:
where:
Step 2: Find the Integrating Factor (IF)
The integrating factor is given by:
Computing the integral:
Thus, the integrating factor is:
Step 3: Multiply the Differential Equation by the Integrating Factor
Multiplying everything by , we get:
Since the left-hand side is the derivative of multiplied by the integrating factor, it simplifies to:
Step 4: Integrate Both Sides
Integrating both sides:
Using integration by parts or substitution techniques, solving the right-hand side gives:
Step 5: Solve for
This expression represents the general solution of the given differential equation.
Would you like me to further evaluate the integral explicitly? Let me know how detailed you need the solution.
Related Questions:
- How do you determine the integrating factor for first-order linear differential equations?
- What are the steps to solve first-order linear differential equations?
- How do you apply integration by parts in differential equations?
- What are some real-world applications of first-order linear differential equations?
- How do you solve non-homogeneous differential equations?
Tip:
Always check whether a differential equation is separable before proceeding with other methods. Separable equations are often easier to solve.
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Math Problem Analysis
Mathematical Concepts
First-order linear differential equations
Integrating factors
Differential equations
Integration by parts
Formulas
dy/dx + P(x)y = Q(x)
Integrating factor (IF) = e^(∫P(x)dx)
General solution of a first-order linear differential equation: y = e^(∫P(x)dx)(C + ∫Q(x)e^(∫P(x)dx)dx)
Theorems
Method of integrating factors for linear differential equations
Solution of non-homogeneous first-order linear differential equations
Suitable Grade Level
Grades 11-12
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