I see that you've uploaded an image of a math problem written in Greek. I'll extract and solve the relevant equations from the image. Here's what I can make out:

The problems are related to calculating expressions with integers and powers. Let's break it down:

Expression A:

$A = (-1)^2 - (-1) \cdot 2 - 5 \cdot (-1)^2 - (-2)$

Expression B:

$B = (-3)^3 - (-3)^2 \cdot 3 - 5 \cdot (-2)^2 - (2+3 \cdot 6 - (-2))$

Let me solve these expressions step-by-step.

Solving Expression A:

$A = (-1)^2 - (-1) \cdot 2 - 5 \cdot (-1)^2 - (-2)$ We'll evaluate it step by step:

1. $(-1)^2 = 1$
2. $(-1) \cdot 2 = -2$
3. $5 \cdot (-1)^2 = 5$
4. $-(-2) = +2$

So, $A = 1 - (-2) - 5 + 2 = 1 + 2 - 5 + 2 = 0$

Solving Expression B:

$B = (-3)^3 - (-3)^2 \cdot 3 - 5 \cdot (-2)^2 - (2 + 3 \cdot 6 - (-2))$ Again, we evaluate it step by step:

1. $(-3)^3 = -27$
2. $(-3)^2 = 9$, and $9 \cdot 3 = 27$
3. $(-2)^2 = 4$, and $5 \cdot 4 = 20$
4. $3 \cdot 6 = 18$, and $2 + 18 - (-2) = 22$

So, $B = -27 - 27 - 20 - 22 = -96$

Thus:

• $A = 0$
• $B = -96$

Would you like more details on any part of the process?

Here are 5 related questions to expand your understanding:

1. How do powers of negative numbers behave differently based on whether the exponent is even or odd?
2. Why is distributing multiplication over addition important when simplifying expressions?
3. How would the answer change if any of the constants in the expressions were changed?
4. Can you express $A$ and $B$ in a different form using factorization?
5. How can we generalize these expressions to solve similar problems more quickly?

Tip: Always evaluate exponents and parentheses before moving on to multiplication, division, addition, or subtraction.