https://file.aiquickdraw.com/mathbot/file/17265885215893e3f3voz.jpg

The equation given in the image is:

\[
r = \frac{B}{6}
\]

We need to solve for \( B \).

### Steps:

1. Multiply both sides of the equation by 6 to isolate \( B \):
\[
r \times 6 = \frac{B}{6} \times 6
\]

2. This simplifies to:
\[
6r = B
\]

Thus, the solution is:

\[
B = 6r
\]

Would you like further clarification or details?

Here are 5 related questions to explore:

1. If \( r = 2 \), what is the value of \( B \)?
2. How would you rearrange the equation if you were solving for \( r \) instead of \( B \)?
3. What happens to \( B \) if \( r \) becomes very large?
4. Can you solve the equation if \( r \) is given in terms of another variable?
5. How would the solution change if the denominator were a different constant?

**Tip:** Always remember to perform the same operation on both sides of the equation to maintain balance.

Solve the following equation for B. Be sure to take into account whether a letter is capitalized or not: r = B/6

Learn how to solve the equation r = B/6 for B with a step-by-step explanation. This problem helps students practice algebraic rearrangements and the basic concepts of solving linear equations. Suitable for students in Grades 6-8.

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