Math Problem Statement

Solve compound inequalities, transformations of absolute value functions, calculate triangle angles, and determine if lines are perpendicular.

Solution

Let's go through the problems step by step.

Problem 4b (Compound Inequality):

You need to solve the compound inequality:

2(x2)+71and54x>92(x - 2) + 7 \geq -1 \quad \text{and} \quad 5 - 4x > 9

Step 1: Solve 2(x2)+712(x - 2) + 7 \geq -1: 2(x2)+712(x - 2) + 7 \geq -1 2x4+712x - 4 + 7 \geq -1 2x+312x + 3 \geq -1 2x42x \geq -4 x2x \geq -2

Step 2: Solve 54x>95 - 4x > 9: 54x>95 - 4x > 9 4x>95-4x > 9 - 5 4x>4-4x > 4 x<1x < -1

Final Solution: The solution is the intersection of these two inequalities: x2andx<1x \geq -2 \quad \text{and} \quad x < -1 So, the solution is: 2x<1-2 \leq x < -1

Problem 5 (Transformations of g(x)g(x)):

a. g(x)=3x+23g(x) = 3|x + 2| - 3

  • The vertical stretch factor is 3 (since the coefficient outside the absolute value is 3).
  • There is a horizontal shift to the left by 2 units (since x+2x + 2 means shifting left by 2).
  • There is a vertical shift downward by 3 units (because of the 3-3).

b. g(x)=3x1+4g(x) = -3|x - 1| + 4

  • The negative sign indicates a reflection over the x-axis.
  • The vertical stretch factor is 3 (since the coefficient is -3).
  • There is a horizontal shift to the right by 1 unit (since x1x - 1).
  • There is a vertical shift upward by 4 units (due to the +4+4).

Problem 6 (Triangle Angles):

You are asked to find the unknown angles xx.

a. Triangle with angles 5656^\circ, 7676^\circ, and xx^\circ:

The sum of the interior angles of a triangle is always 180°. x+56+76=180x + 56 + 76 = 180 x+132=180x + 132 = 180 x=48x = 48^\circ

b. Triangle with angles 2323^\circ, 7474^\circ, and xx^\circ:

Similarly, for this triangle: x+23+74=180x + 23 + 74 = 180 x+97=180x + 97 = 180 x=83x = 83^\circ

Problem 7 (Perpendicular Lines):

To determine if two lines are perpendicular, check their slopes. Two lines are perpendicular if the product of their slopes is 1-1. In other words, if one line has slope m1m_1 and the other line has slope m2m_2, then:

m1×m2=1m_1 \times m_2 = -1

Do you want more detailed explanations for any of these, or have further questions?

Here are 5 related questions to explore further:

  1. How do you solve compound inequalities involving "or" instead of "and"?
  2. What happens to the graph of an absolute value function when you change the sign of aa or bb?
  3. How do you find the slopes of two lines if only their equations are given?
  4. Can you solve a system of inequalities graphically?
  5. How does reflecting a function over the x-axis change its graph?

Tip: When solving for the angles of a triangle, remember that the sum is always 180°, and you can apply this in any triangle geometry problem!

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Math Problem Analysis

Mathematical Concepts

Inequalities
Absolute Value Functions
Triangle Angles
Slopes of Lines

Formulas

Compound Inequality Solving
g(x) = a|x - h| + k (Transformations of Absolute Value Functions)
Sum of Interior Angles in a Triangle: 180°
Slopes of Perpendicular Lines: m1 * m2 = -1

Theorems

Angle Sum Theorem (Triangles)
Perpendicular Lines Theorem

Suitable Grade Level

Grades 9-11