Math Problem Statement

Can you answer the last question

Can you answer the last question?

Solution

Let's solve the last question, which asks us to find the composite function and select the correct choice.

We are given two functions:

  • f(x)=x2f(x) = x^2
  • g(x)=20+xg(x) = 20 + x

We need to evaluate f(g(x))f(g(x)) and g(f(x))g(f(x)), which represent the compositions of functions.

1. fg(x)=f(g(x))f \circ g(x) = f(g(x))

To find f(g(x))f(g(x)), substitute g(x)=20+xg(x) = 20 + x into f(x)=x2f(x) = x^2: f(g(x))=f(20+x)=(20+x)2f(g(x)) = f(20 + x) = (20 + x)^2 So, f(g(x))=(20+x)2f(g(x)) = (20 + x)^2.

Thus, the correct answer for f(g(x))f(g(x)) is: B.y=f(g(x))=(20+x)2B. \, y = f(g(x)) = (20 + x)^2

2. gf(x)=g(f(x))g \circ f(x) = g(f(x))

To find g(f(x))g(f(x)), substitute f(x)=x2f(x) = x^2 into g(x)=20+xg(x) = 20 + x: g(f(x))=g(x2)=20+x2g(f(x)) = g(x^2) = 20 + x^2 So, g(f(x))=20+x2g(f(x)) = 20 + x^2.

The correct answer for g(f(x))g(f(x)) is: A.y=g(f(x))=20+x2A. \, y = g(f(x)) = 20 + x^2

Both the answers provided are correct as per your choices:

  • f(g(x))=(20+x)2f(g(x)) = (20 + x)^2
  • g(f(x))=20+x2g(f(x)) = 20 + x^2

Let me know if you'd like further details or clarification! Here are five questions related to this topic:

  1. What is the difference between fg(x)f \circ g(x) and gf(x)g \circ f(x)?
  2. How do you prove the properties of composite functions?
  3. Can the order of composition change the result?
  4. What are some real-world applications of composite functions?
  5. How do composite functions relate to inverse functions?

Tip: When composing functions, always start by substituting the inside function into the outside function.

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Math Problem Analysis

Mathematical Concepts

Function Composition
Algebra

Formulas

f(g(x)) = f(20 + x) = (20 + x)^2
g(f(x)) = g(x^2) = 20 + x^2

Theorems

Function Composition Theorem

Suitable Grade Level

Grades 10-12