This is a math puzzle where each row and column contains an arithmetic operation (addition, subtraction, multiplication, or division). The goal is to fill in the missing numbers so that the operations yield the results given on the right and bottom of the grid.

Let me break down the process and solve the puzzle step by step:

Analyzing the Grid

• Operations in Rows:

  • Row 1: A + B + C + D = -22
  • Row 2: E × F + G + H = -23
  • Row 3: I + J × K + L = 384
  • Row 4: M + N + O × P = -5

• Operations in Columns:

  • Column 1: A + E + I + M = 39
  • Column 2: B + F + J + N = -10
  • Column 3: C + G + K + O = 36
  • Column 4: D + H + L + P = 89

Let's start solving by considering some logical deductions based on the arithmetic operations.

Step 1: Solving the Third Row (Row 3)

The equation is: $I + J \times K + L = 384$

We know:

• $I = 48$
• $J = 6$
• $K = 64$
• $L = 0$

Let's substitute these values: $48 + 6 \times 64 + 0 = 48 + 384 + 0 = 384$

This row is already correct.

Step 2: Deduce from the Columns

Using the numbers from Row 3 and looking at the operations in the columns:

1. Column 1 (A, E, I, M): $A + E + 48 + M = 39$
2. Column 2 (B, F, J, N): $B + F + 6 + N = -10$
3. Column 3 (C, G, K, O): $C + G + 64 + O = 36$
4. Column 4 (D, H, L, P): $D + H + 0 + P = 89$

We'll need to make more educated guesses based on the multiplication and addition patterns.

Step 3: Solving Each Row

Let's consider Row 1 (A + B + C + D = -22):

1. Choose A and B based on Column 1 and Column 2 calculations.
2. Choose C and D based on remaining values.

Let's assign numbers that satisfy both the rows and columns progressively:

Final Grid (Possible Solution)