Math Problem Statement

jawablah pertanyaan berikut dengan benar

jawablah pertanyaan berikut dengan benar

Solution

Let's work through the problems step by step:

Question 9:

The general formula for the sequence is Un=n2+1U_n = n^2 + 1.

To find the first five terms, we plug values for n=1,2,3,4,5n = 1, 2, 3, 4, 5 into the formula:

  1. U1=12+1=2U_1 = 1^2 + 1 = 2
  2. U2=22+1=5U_2 = 2^2 + 1 = 5
  3. U3=32+1=10U_3 = 3^2 + 1 = 10
  4. U4=42+1=17U_4 = 4^2 + 1 = 17
  5. U5=52+1=26U_5 = 5^2 + 1 = 26

Thus, the first five terms are: 2, 5, 10, 17, 26.

So, the correct answer is C. 2, 5, 10, 17, 26.


Question 10:

The given sequence is 5, 9, 13, 17, ...

This is an arithmetic sequence with a common difference of 4. The general term for an arithmetic sequence is given by: Un=U1+(n1)dU_n = U_1 + (n-1) \cdot d where U1U_1 is the first term and dd is the common difference.

For this sequence:

  • U1=5U_1 = 5
  • d=4d = 4

Thus, the nth term will be: Un=5+(n1)4=5+4n4=4n+1U_n = 5 + (n-1) \cdot 4 = 5 + 4n - 4 = 4n + 1

So, the correct answer is B. Un=1+4nU_n = 1 + 4n.


Question 11:

For a geometric sequence, the formula for the nth term is given by: Un=U1r(n1)U_n = U_1 \cdot r^{(n-1)} Where:

  • U1=8U_1 = 8
  • U6=14U_6 = \frac{1}{4}

We need to find the common ratio rr. The relationship between U1U_1 and U6U_6 is: U6=8r(61)=8r5=14U_6 = 8 \cdot r^{(6-1)} = 8 \cdot r^5 = \frac{1}{4} Solving for rr: 8r5=148 \cdot r^5 = \frac{1}{4} r5=132r^5 = \frac{1}{32} Taking the 5th root of both sides: r=12r = \frac{1}{2}

So, the correct answer is E. r=12r = \frac{1}{2}.


Question 12:

The sequence is 32, 16, 8, 4, ...

This is a geometric sequence, and we can find the ratio by dividing the second term by the first term: 1632=12\frac{16}{32} = \frac{1}{2}

So, the ratio is 12\frac{1}{2}.

The correct answer is E. 12\frac{1}{2}.


Question 13:

We need to solve for xx in the equation: 4x16+x=2313x2\frac{4x - 1}{6} + x = \frac{2}{3} \cdot \frac{1 - 3x}{2} Start by simplifying both sides:

  • Left-hand side: 4x16+x=4x16+6x6=4x1+6x6=10x16\frac{4x - 1}{6} + x = \frac{4x - 1}{6} + \frac{6x}{6} = \frac{4x - 1 + 6x}{6} = \frac{10x - 1}{6}
  • Right-hand side: 2313x2=13x3\frac{2}{3} \cdot \frac{1 - 3x}{2} = \frac{1 - 3x}{3}

Now, set the two expressions equal: 10x16=13x3\frac{10x - 1}{6} = \frac{1 - 3x}{3} Cross-multiply to eliminate the denominators: 3(10x1)=6(13x)3(10x - 1) = 6(1 - 3x) Simplify both sides: 30x3=618x30x - 3 = 6 - 18x Move all terms involving xx to one side: 30x+18x=6+330x + 18x = 6 + 3 48x=948x = 9 Solve for xx: x=948=316x = \frac{9}{48} = \frac{3}{16}

So, the correct answer is None of the provided options.


Would you like more details or clarifications on any of these steps? Let me know if you'd like me to explain further!

Related questions:

  1. How do you identify whether a sequence is arithmetic or geometric?
  2. How do you calculate the common ratio of a geometric sequence?
  3. How do you solve for xx in a linear equation with fractions?
  4. Can you explain the 5th root in the geometric sequence question?
  5. What’s the general formula for the nth term in an arithmetic sequence?

Tip: When working with sequences, always first identify whether the sequence is arithmetic (constant difference) or geometric (constant ratio). This can help you apply the right formulas.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Geometric Sequences
Linear Equations

Formulas

U_n = n^2 + 1
U_n = U_1 + (n-1) * d
U_n = U_1 * r^(n-1)

Theorems

Arithmetic Sequence Formula
Geometric Sequence Formula
Solving Linear Equations

Suitable Grade Level

Grades 9-12