Math Problem Statement

If ๐˜ฎโˆ ๐˜•๐˜–๐˜—=๐Ÿค๐˜น+๐Ÿค, ๐˜ฎโˆ ๐˜—๐˜–๐˜™=๐Ÿฅ๐˜นโˆ’๐Ÿง,m normal angle upper P upper O upper R times equals 3 times sans-serif-italic x minus 5 comma and ๐˜ฎโˆ ๐˜•๐˜–๐˜˜=๐Ÿฃ๐Ÿฃ๐Ÿฆ, what is the value of x?

Solution

Given the angles mโˆ NOP=2x+2m\angle NOP = 2x + 2, mโˆ POR=3xโˆ’5m\angle POR = 3x - 5, and mโˆ NOQ=144โˆ˜m\angle NOQ = 144^\circ, we are asked to find the value of xx.

Assuming that points NN, OO, PP, QQ, and RR are on a straight line or form a linear pair (since mโˆ NOQ=144โˆ˜m\angle NOQ = 144^\circ), we can deduce that the angles mโˆ NOPm\angle NOP and mโˆ PORm\angle POR must sum up to mโˆ NOQm\angle NOQ. Thus, we have the equation:

mโˆ NOP+mโˆ POR=mโˆ NOQm\angle NOP + m\angle POR = m\angle NOQ

Substituting the given expressions for the angles:

(2x+2)+(3xโˆ’5)=144(2x + 2) + (3x - 5) = 144

Now, let's simplify and solve for xx:

2x+3x+2โˆ’5=1442x + 3x + 2 - 5 = 144

5xโˆ’3=1445x - 3 = 144

Add 3 to both sides:

5x=1475x = 147

Finally, divide by 5:

x=1475=29.4x = \frac{147}{5} = 29.4

So, the value of xx is 29.4.

Would you like a detailed explanation or have any questions?

Here are 5 related questions:

  1. What is the measure of mโˆ NOPm\angle NOP when x=29.4x = 29.4?
  2. How would you check if the angles sum correctly when x=29.4x = 29.4?
  3. Can the value of xx be negative in this scenario?
  4. What assumptions are made about the relationship between points NN, OO, PP, QQ, and RR?
  5. How would the problem change if mโˆ NOQm\angle NOQ was different?

Tip: Always verify your final answer by substituting it back into the original equations to ensure all conditions are met.

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Math Problem Analysis

Mathematical Concepts

Geometry
Linear pairs
Angles

Formulas

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Theorems

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Suitable Grade Level

Grades 9-12