Math Problem Statement

In the diagram, ∠PQR = 125°, ∠QRS = r, ∠RST = 80°, and ∠STU = 44°. Calculate the value of r.

Solution

Let's analyze the diagram and the given information to solve for angle rr.

We are provided with the following:

  • PQR=125\angle PQR = 125^\circ
  • QRS=r\angle QRS = r (This is the unknown we are asked to find)
  • RST=80\angle RST = 80^\circ
  • STU=44\angle STU = 44^\circ

Step 1: Identify the straight-line properties

From the diagram, points PP, QQ, and RR appear to lie on a straight line, and points SS, RR, and TT seem to form another line. So, we can use the straight angle property, which tells us that the sum of the angles on a straight line is 180180^\circ.

Step 2: Calculate rr using angles on a straight line

We know that: \angle PQR + \angle QRS = 180^\circ \quad \text{(since PQR forms a straight line)} Substitute the given value of PQR=125\angle PQR = 125^\circ: 125+r=180125^\circ + r = 180^\circ Solving for rr: r=180125=55r = 180^\circ - 125^\circ = 55^\circ

Thus, the value of rr is 5555^\circ.

Would you like more details, or do you have any questions about this? Here are some related questions:

  1. How do we know that PQR\angle PQR and QRS\angle QRS form a straight line?
  2. What is the property of angles on a straight line?
  3. How would you apply the same reasoning to different geometric configurations?
  4. Could other angle properties, like alternate interior angles, apply here?
  5. How does this calculation change if a different angle is altered?

Tip: When solving for unknown angles, always check if you can apply the property of angles on a straight line or around a point (both of which sum to 180° and 360° respectively).

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Math Problem Analysis

Mathematical Concepts

Geometry
Angles on a Straight Line

Formulas

Sum of angles on a straight line = 180°

Theorems

Straight angle theorem

Suitable Grade Level

Grades 6-8