Math Problem Statement

Question content area top

Part 1

Solve

xplus+1212less than or equals≤1818​,

and then graph the solutions.

Solution

Given inequality:

x+1218x + 12 \leq 18

Step 1: Solve for xx

To isolate xx, subtract 12 from both sides of the inequality:

x+12121812x + 12 - 12 \leq 18 - 12

This simplifies to:

x6x \leq 6

So, the solution is:

x6x \leq 6

Step 2: Graph the solutions

The solution x6x \leq 6 means that xx can be any value less than or equal to 6. On a number line, we represent this by:

  1. Drawing a solid circle at 6 (since xx can be equal to 6).
  2. Shading the region to the left of 6 to show that all values less than or equal to 6 are included in the solution.

Number Line:

<---●========>
       6

The solid circle at 6 indicates that 6 is included in the solution, and the arrow to the left shows that all smaller numbers are also solutions.

Final Answer:

  • The solution is x6x \leq 6.
  • The graph shows a solid circle at 6 with shading to the left.

Would you like to work through more inequalities or explore other types of equations?

Related Questions:

  1. How would you graph the inequality x>3x > 3?
  2. What is the solution to 2x482x - 4 \geq 8?
  3. How do you solve and graph 5x+10<255x + 10 < 25?
  4. What happens if the inequality is x32x - 3 \leq 2? How would you solve it?
  5. If the inequality was 4x164x \geq 16, what would the solution be?

Tip: When graphing inequalities, remember that a solid circle means "included" (≤ or ≥), while an open circle means "not included" (< or >)!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Inequalities
Graphing Inequalities

Formulas

Solving linear inequalities
Graphing on a number line

Theorems

Properties of inequalities

Suitable Grade Level

Grades 6-8